refactor: 优化 getMyRecentScore 函数中的消息构建逻辑,合并消息构建步骤以提升代码简洁性
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@ -304,20 +304,20 @@ func getMyRecentScore(msg model.Message) (reply *model.Reply) {
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}
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}
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//如果消息行数太多,使用合并转发
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//如果消息行数太多,使用合并转发
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if len(records) > 5 {
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if len(records) > 5 {
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var nodeMsgs []message.NodeMessage
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nodeMsg := util.NewSelfNodeMessage(append(
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nodeMsg := util.NewSelfNodeMessage(&message.TextMessage{
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[]any{
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&message.TextMessage{
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Type: "text",
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Type: "text",
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Data: message.TextMessageData{
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Data: message.TextMessageData{
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Text: "玩家 " + userName + " 的" + strconv.Itoa(recordCount) + "条最近记录为:\n",
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Text: "玩家 " + userName + " 的" + strconv.Itoa(recordCount) + "条最近记录为:\n",
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},
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},
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})
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},
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nodeMsgs = append(nodeMsgs, *nodeMsg)
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},
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for _, msg := range scoreMsg {
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scoreMsg...,
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nodeMsgs = append(nodeMsgs, *util.NewSelfNodeMessage(msg))
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)...)
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}
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action.ActionManager.SendForward(
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action.ActionManager.SendForward(
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&model.Reply{
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&model.Reply{
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ReplyMsg: nodeMsgs,
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ReplyMsg: nodeMsg,
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ReferOriginMsg: false,
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ReferOriginMsg: false,
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FromMsg: msg,
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FromMsg: msg,
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},
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},
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@ -327,7 +327,7 @@ func getMyRecentScore(msg model.Message) (reply *model.Reply) {
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return &model.Reply{
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return &model.Reply{
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ReplyMsg: append(
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ReplyMsg: append(
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[]any{
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[]any{
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&message.TextMessage{
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message.TextMessage{
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Type: "text",
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Type: "text",
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Data: message.TextMessageData{
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Data: message.TextMessageData{
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Text: "玩家 " + userName + " 的" + strconv.Itoa(recordCount) + "条最近记录为:",
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Text: "玩家 " + userName + " 的" + strconv.Itoa(recordCount) + "条最近记录为:",
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